20x^4-12x^2+1=0

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Solution for 20x^4-12x^2+1=0 equation:


Simplifying
20x4 + -12x2 + 1 = 0

Reorder the terms:
1 + -12x2 + 20x4 = 0

Solving
1 + -12x2 + 20x4 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + -10x2)(1 + -2x2) = 0

Subproblem 1

Set the factor '(1 + -10x2)' equal to zero and attempt to solve: Simplifying 1 + -10x2 = 0 Solving 1 + -10x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -10x2 = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -10x2 = 0 + -1 -10x2 = 0 + -1 Combine like terms: 0 + -1 = -1 -10x2 = -1 Divide each side by '-10'. x2 = 0.1 Simplifying x2 = 0.1 Take the square root of each side: x = {-0.316227766, 0.316227766}

Subproblem 2

Set the factor '(1 + -2x2)' equal to zero and attempt to solve: Simplifying 1 + -2x2 = 0 Solving 1 + -2x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2x2 = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2x2 = 0 + -1 -2x2 = 0 + -1 Combine like terms: 0 + -1 = -1 -2x2 = -1 Divide each side by '-2'. x2 = 0.5 Simplifying x2 = 0.5 Take the square root of each side: x = {-0.707106781, 0.707106781}

Solution

x = {-0.316227766, 0.316227766, -0.707106781, 0.707106781}

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